# Posts Tagged Design of Doubly reinforced sections

### Design of Doubly reinforced sections | Numerical example

Posted by BenzuJK in Building Construction on September 24, 2012

#### 7 step design procedure for Doubly reinforced sections

**In our article series for “Design of Doubly reinforced sections”, we covered the following:**

What are doubly reinforced sections?

Methods for determining Neutral Axis?

Solved numerical examples for determining Neutral Axis

Numerical examples for practice (Find Neutral axis)

Methods for calculating Moment of Resistance

Numerical example for calculating Moment of resistance

Types of problems in Doubly reinforced sections

6 step prodecure for determining stresses in steel and concrete

Numerical example | Stresses in steel and concrete

7 step procedure for designing doubly reinforced sections

**We shall now proceed with a numerical example “Design of Doubly reinforced sections” using the 7-step procedure we discussed in the previous article.**

**Numerical problem:**

A doubly reinforced concrete beam 250mm wide and 600mm deep overall has to resist an external bending moment of 95kN-m. Find the amount of tensile and compressive steel required, if cover to the centre of steel on both sides is 50mm. σ_{cbc }= 5 N/mm^{2}, σ_{st }= 140 N/mm^{2}, m = 18.66

**Given that:**

Breadth of the beam = b = 250mm

Effective depth of the beam = d = 600 – 50 = 550mm

Distance of compressive steel from the top edge of the beam to the centre of the steel = d’ = 50mm

Permissible stress in concrete = σ_{cbc }= 5 N/mm^{2}

Permissible stress in steel = σ_{st} = 140 N/mm^{2}

Modular ratio = m = 18.66

Bending moment = M = 95 kN-m

#### Step one:

To find x_{c}

σ_{cbc}/ (σ_{st}/m) = x_{c}/(d – x_{c})

5/(140/18.66) = x_{c}/(550 – x_{c})

x_{c} = 219.95 = 220mm

### Types of Problems | Design of Doubly Reinforced Sections

Posted by BenzuJK in Building Construction on August 7, 2012

**Stepwise procedure for calculating Moment of resistance and compressive stresses in steel and concrete**

**While we proceed with the article series for “Doubly reinforced sections”, I would like to categorize the problems into different types. This will make your understanding of the concept better and concrete. I recommend that you practice enough to be able to understand and confidently solve the problems. This will also help you in real time when you would get into practice.**

#### In our article series for doubly reinforced sections, we have covered the following:

What are doubly reinforced sections?

Methods for determining Neutral Axis?

Solved numerical examples for determining Neutral Axis

Numerical examples for practice (Find Neutral axis)

Methods for calculating Moment of Resistance

Numerical example for calculating Moment of resistance

Types of problems in Doubly reinforced sections

Determining stresses in steel and concrete

Numerical example | Stresses in steel and concrete

**Also check out: “Singly reinforced Sections” article series.**

**So let’s begin with different types of problems for “Doubly reinforced sections”.**

#### Problem type 1

**To find Moment of resistance (Mr)**

**In a problem where we have to find Mr, specific data is given so that you could calculate the Moment of resistance. The following data will be given in the problem. I suggest that you make notes of the points below.**

Breadth of the beam = b

Effective depth of the beam = d

Area of tensile steel = Ast

Area of compressive steel = Asc

Permissible stress in concrete = σcbc

Permissible stress in steel = σst

Modular ratio = m

#### Four – step procedure to solving the problem:

**Step one:**

**Find x _{c} by the following formula,**

σ_{cbc}/ (σ_{st}/m) = x_{c}/(d-x_{c})

**Step two:**

Find x using the following formula,

bxx/2 + (1.5m – 1)Asc (x – d’) = m Ast (d – x)

### Moment of Resistance | Doubly reinforced Sections

Posted by BenzuJK in Building Construction on July 31, 2012

#### Methods for calculating Moment of resistance for Doubly reinforced beam

**In our article series for “Doubly reinforced sections”, we have covered the following:**

What are doubly reinforced sections?

Methods for determining Neutral Axis?

Solved numerical examples for determining Neutral Axis

Numerical examples for practice (Find Neutral axis)

Methods for calculating Moment of Resistance

Numerical example for calculating Moment of resistance

Types of problems in Doubly reinforced sections

Determining stresses in steel and concrete

Numerical example | Stresses in steel and concrete

**Also check out: “Singly reinforced Sections” article series.**

**Now, our next step would be to study different methods for calculating moment of resistance (MR).**

#### Two methods for calculating Moment of Resistance

**There are two methods for calculating the moment of resistance of doubly reinforced sections. They are as follows:**

- Method 1 – Elastic theory
- Method 2 – Steel beam theory

#### Method 1

**Method using Elastic theory**

The moment of resistance is calculated by taking the moments of forces about the centre of gravity of the tensile steel.

**From the figure above, we get,**

Mr = Moment of compressive force of concrete about tensile steel + Moment of equivalent concrete force of compression steel about tensile steel

= bx(σcbc/2)(d – x/3) + (1.5m – 1)Asc. σcbc (d – d’)

Where, (1.5m – 1)Asc is the equivalent concrete area of compression steel.

### Neutral Axis – Solved Example | Doubly reinforced Sections

Posted by BenzuJK in Building Construction on July 30, 2012

#### Guide to design of Doubly reinforced Beam

**In our article series for “Doubly reinforced sections”, we have covered the following:**

What are doubly reinforced sections?

Methods for determining Neutral Axis?

Solved numerical examples for determining Neutral Axis

Numerical examples for practice (Find Neutral axis)

Methods for calculating Moment of Resistance

Numerical example for calculating Moment of resistance

Types of problems in Doubly reinforced sections

Determining stresses in steel and concrete

Numerical example | Stresses in steel and concrete

**Now we shall move on with a solved example. This will help you understand the methods in a better way. I suggest that you do them yourselves too. Practice will help you make your concepts more concrete and clear.**

#### Example:

**An reinforced concrete beam 200mm x 400mm overall is reinforced with 4 – 22mm⏀ bars with centres 30mm from the bottom edge and 3 – 20mm⏀ bars with centres 25mm from the top edge. Find the neutral axis of the beam, if m = 18.66**

**Given that,**

Width of the beam = 200mm

Effective depth of the beam = 400 – 30 = 370mm

Distance of compressive steel from the top edge of the beam to the centre of the steel = d’ = 25mm

Modular ratio = m = 18.66

Area of concrete = Asc = 3 x π/4 x (20)^{2} = 942 mm^{2}

Area of tensile steel = Ast = 4 x π/4 x (22)^{2} = 1520 mm^{2}

#### To find x:

**Equating moment of area on compression and tension sides about N.A.**

**bxx/2 + (1.5m – 1)A _{sc}(x – d’) = mAst (d – x)**

200x^{2}/2 + (1.5 x 18.66 – 1) 942 (x – 25)

= 18.66 x 1520 (370 – x)

Therefore, x2 + 537.87x – 111299 = 0

**Solving the above equation, we get,**

x = 159.579mm

#### Examples for practice

**An reinforced concrete beam 300mm x 600mm overall is reinforced with 6 – 22mm⏀ bars with centres 30mm from the bottom edge and 5 – 20mm⏀ bars with centres 25mm from the top edge. Find the neutral axis of the beam, if m = 18.66**

**An reinforced concrete beam 300mm x 600mm overall is reinforced with 4 – 20mm⏀ bars with centres 25mm from the bottom edge and 6 – 20mm⏀ bars with centres 25mm from the top edge. Find the neutral axis of the beam, if m = 18.66**

### Guide to design of Doubly reinforced Sections | Civil Engineering

Posted by BenzuJK in Building Construction on July 29, 2012

#### What are Doubly reinforced sections?

Sections that have tensile as well as compressive reinforcement are called doubly reinforced sections.

#### Necessity of design of doubly reinforced sections

When the dimensions of the beam are restricted for architectural or structural considerations, the section has insufficient area of concrete which results in inability of the beam to take sufficient compressive stresses. If not paid attention to, it could result in structural failure.

To solve this problem, steel is placed in the compressive area of the section to help the concrete section in resisting compressive stresses. (Steel is good at taking up both compression and tension.)

In this way, the moment of resistance of the section is increased without altering its dimensions.

#### Three important conditions where doubly reinforced sections are to be used:

1) When the dimensions of the beam are restricted for architectural or structural purposes.

2) Sections that are subjected to the reversal of bending moment (piles, braces in water towers etc.

3) The portion of the beam over middle support in continuous T beams has to be designed as doubly reinforced section.

**We are now going to begin with a series of articles on “Design of Doubly reinforced sections”. In our previous series of articles for “Singly reinforced sections“, we have covered every step in detail for the design and analysis of Singly reinforced sections.**

#### We would be covering the following for “Doubly reinforced Sections”:

What are doubly reinforced sections?

Methods for determining Neutral Axis?

Solved numerical examples for determining Neutral Axis

Numerical examples for practice (Find Neutral axis)

Methods for calculating Moment of Resistance

Numerical example for calculating Moment of resistance

Types of problems in Doubly reinforced sections

Determining stresses in steel and concrete

Numerical example | Stresses in steel and concrete

**So let us begin with understanding the methods for determining the neutral axis for doubly reinforced sections.**

#### Methods of determining Neutral axis for doubly reinforced sections

#### METHOD ONE:

**Given that:**

Dimensions of the beam:

b = width of the beam, d = depth of the beam

Permissible stresses in concrete = σ_{cbc}

Permissible stress in steel = σ_{st}

Modular ratio = m

**From similar triangles in the equivalent concrete stress diagram,**

σ_{cbc}/ (σ_{st}/m) = x_{c}/(d – x_{c})