Numerical Examples for Chain Surveying | Errors in Surveying





Numerical Examples for Errors in Chain Surveying

We will now move on with different numerical problems on the concept of Errors in Chain Surveying. Going through these numericals will actually give you an idea as to how the calculations are done inspite of errors occurring in the Chain Surveying.

Correction due to incorrect length of chain

This is like a formula list which is to be kept in mind while making Calculations:

True distance = L’/L*measured distance

True area = (L’/L)2*measured area

True Volume = (L’/L)3 * measured volume

Where, L’ = incorrect length of chain

L = correct length of chain

The length of a line measured with 20m chain was found to be 500m. It was subsequently found that the chain was 0.04m too long. What is the length of line?

Correct length of chain, L’ = 20 + 0.04 = 20.04m

Length, L = 20m

Measured length, = 500m

True length = (L’/L) * measured length

= (20.04/20) * 500

= 501m

We will continue with more examples on the same topic in our successive articles…



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  1. #1 by amma anandkumar on September 8, 2015 - 11:10 pm

    This methods are very use full to the survey

  2. #2 by ganesh dutta on August 8, 2015 - 11:50 pm

    I want more examples

  3. #3 by Mugo. on July 6, 2012 - 3:00 am

    Thanx for the tips on survey. Really helps

  4. #4 by aunik on March 17, 2012 - 7:44 am

    i need some important solution of some problem.
    the distance between two stations was found to be 5305ft.when measured by an Engineering chain & 7946 links by Gunter’s chain.both of the chain were incorrect.what correction is needed in the Engineering chain if the Gunter’s chains 0.4 links too long?

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