#### Guide to design of Doubly reinforced Beam

**In our article series for “Doubly reinforced sections”, we have covered the following:**

What are doubly reinforced sections?

Methods for determining Neutral Axis?

Solved numerical examples for determining Neutral Axis

Numerical examples for practice (Find Neutral axis)

Methods for calculating Moment of Resistance

Numerical example for calculating Moment of resistance

Types of problems in Doubly reinforced sections

Determining stresses in steel and concrete

Numerical example | Stresses in steel and concrete

**Now we shall move on with a solved example. This will help you understand the methods in a better way. I suggest that you do them yourselves too. Practice will help you make your concepts more concrete and clear.**

#### Example:

**An reinforced concrete beam 200mm x 400mm overall is reinforced with 4 – 22mm⏀ bars with centres 30mm from the bottom edge and 3 – 20mm⏀ bars with centres 25mm from the top edge. Find the neutral axis of the beam, if m = 18.66**

**Given that,**

Width of the beam = 200mm

Effective depth of the beam = 400 – 30 = 370mm

Distance of compressive steel from the top edge of the beam to the centre of the steel = d’ = 25mm

Modular ratio = m = 18.66

Area of concrete = Asc = 3 x π/4 x (20)^{2} = 942 mm^{2}

Area of tensile steel = Ast = 4 x π/4 x (22)^{2} = 1520 mm^{2}

#### To find x:

**Equating moment of area on compression and tension sides about N.A.**

**bxx/2 + (1.5m – 1)A _{sc}(x – d’) = mAst (d – x)**

200x^{2}/2 + (1.5 x 18.66 – 1) 942 (x – 25)

= 18.66 x 1520 (370 – x)

Therefore, x2 + 537.87x – 111299 = 0

**Solving the above equation, we get,**

x = 159.579mm

#### Examples for practice

**An reinforced concrete beam 300mm x 600mm overall is reinforced with 6 – 22mm⏀ bars with centres 30mm from the bottom edge and 5 – 20mm⏀ bars with centres 25mm from the top edge. Find the neutral axis of the beam, if m = 18.66**

**An reinforced concrete beam 300mm x 600mm overall is reinforced with 4 – 20mm⏀ bars with centres 25mm from the bottom edge and 6 – 20mm⏀ bars with centres 25mm from the top edge. Find the neutral axis of the beam, if m = 18.66**

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#1 by

Anandon May 27, 2015 - 1:27 amHi Thanks for the tutition

I have a problem with taking area moments about the nuetral axis

bxx/2 + (1.5m – 1)Asc(x – d’) = mAst (d – x)

I am trying to find guidence on how the area moments were taken.

Only one other source had expanded the line above from

bx2/2-As'(x-d’)+mA’s(x-d’)=mAs(d-x)

where As’ is the area of compression steel

Can you please explain why -As'(x-d’)+mA’s(x-d’) is taken as negative and positive moments please